Remove Element
描述
Given an array and a value, remove all instances of that value in place and return the new length.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
分析
无
代码
- Python
- Java
- C++
# Remove Element
# 双指针
# Time Complexity: O(n), Space Complexity: O(1)
class Solution:
def removeElement(self, nums: List[int], target: int) -> int:
slow = 0
for fast in range(len(nums)):
if nums[fast] != target:
nums[slow] = nums[fast]
slow += 1
return slow
// Remove Element
// 双指针
// Time Complexity: O(n), Space Complexity: O(1)
public class Solution {
public int removeElement(int[] nums, int target) {
int slow = 0;
for (int fast = 0; fast < nums.length; ++fast) {
if (nums[fast] != target) {
nums[slow++] = nums[fast];
}
}
return slow;
}
};
// Remove Element
// 双指针
// Time Complexity: O(n), Space Complexity: O(1)
class Solution {
public:
int removeElement(vector<int>& nums, int target) {
int slow = 0;
for (int fast = 0; fast < nums.size(); ++fast) {
if (nums[fast] != target) {
nums[slow++] = nums[fast];
}
}
return slow;
}
};