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Add Two Numbers

描述

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)

Output: 7 -> 0 -> 8

分析

Add Binary 很类似

代码

// Add Two Numbers
// 跟Add Binary 很类似
// 时间复杂度O(m+n),空间复杂度O(1)
public class Solution {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
ListNode dummy = new ListNode(-1); // 头节点
int carry = 0;
ListNode prev = dummy;
for (ListNode pa = l1, pb = l2;
pa != null || pb != null;
pa = pa == null ? null : pa.next,
pb = pb == null ? null : pb.next,
prev = prev.next) {
final int ai = pa == null ? 0 : pa.val;
final int bi = pb == null ? 0 : pb.val;
final int value = (ai + bi + carry) % 10;
carry = (ai + bi + carry) / 10;
prev.next = new ListNode(value); // 尾插法
}
if (carry > 0)
prev.next = new ListNode(carry);
return dummy.next;
}
};

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