# Isomorphic Strings

### 描述​

Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,

Given "egg", "add", return true.

Given "foo", "bar", return false.

Given "paper", "title", return true.

Note:

You may assume both s and t have the same length.

### 代码​

// Isomorphic Strings// Time Complexity: O(n), Space Complexity: O(n)public class Solution {    public boolean isIsomorphic(String s, String t) {        if (s.length() != t.length()) return false;        final Map<Character,Character> map1 = new HashMap<>();        final Map<Character,Character> map2 = new HashMap<>();        for (int  i = 0; i < s.length(); ++i) {            final char c1 = s.charAt(i);            final char c2 = t.charAt(i);            if (map1.containsKey(c1)) {                if (map1.get(c1) != c2) return false;            } else {                map1.put(c1, c2);            }            if (map2.containsKey(c2)) {                if (map2.get(c2) != c1) return false;            } else {                map2.put(c2, c1);            }        }        return true;    }}