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Serialize and Deserialize Binary Tree

描述

Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.

Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure.

Clarification: The input/output format is the same as how LeetCode serializes a binary tree. You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.

Example 1:

  1
/ \
2 3
/ \
4 5

Input: root = [1,2,3,null,null,4,5]
Output: [1,2,3,null,null,4,5]

Example 2:

Input: root = []
Output: []

Example 3:

Input: root = [1]
Output: [1]

Example 4:

Input: root = [1,2]
Output: [1,2]

Constraints:

  • The number of nodes in the tree is in the range [0, 10410^4].
  • 1000Node.val1000-1000 \leq Node.val \leq 1000

分析

这题本质上考的是二叉树的遍历,前序,中序,后序,BFS,无论哪种都可以。

注意,空叶子节点也必须编码为"null",这样才能保存完整的树结构。

代码

# Serialize and Deserialize Binary Tree
# Time Complexity O(n), Space Complexity O(n)
class Codec:

def serialize(self, root):
return self.serializeDFS(root, "")

def serializeDFS(self, root, string: str):
if root is None:
string += "null,"
else:
string += str(root.val) + ","
string = self.serializeDFS(root.left, string)
string = self.serializeDFS(root.right, string)
return string

def deserialize(self, data):
return self.deserializeDFS(data.split(','))

def deserializeDFS(self, l):
if l[0] == 'null':
l.pop(0)
return None

root = TreeNode(l[0])
l.pop(0)
root.left = self.deserializeDFS(l)
root.right = self.deserializeDFS(l)
return root

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